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<< XQuery.NET and XML >>

By Dimitre Novatchev
First Posted 03/22/2001
Times viewed 315

Identifying an attribute or a namespace node

Summary Presented is a common technique to determine whether the type of a node is attribute or a namespace.

Whenever you have to perform a more general processing of an xml document, whose type is not known in advance (e.g. as in an XSL Debugger or in a XPath visualisation tool), you need to be able to determine the concrete type of a (any) node. While for node types for which a node-test exists this is straightforward e.g: self::* -- tests if the current node is an element self::text() -- tests whether the current node is a text node self::comment() -- tests whether the current node is a comment node self::processing-instruction() -- tests whether the current node is a processing instruction self::node() -- tests that the current node is all of the above or the root node self::someName -- tests whether the current node is an element having the name someName there isn't any straightforward way to determine if the current node is an attribute or a namespace. This is because in XPAth there isn't a node-test for attribute or namespace nodes. If we try the following: self::attribute we are asking whether the current node is ***an element*** with name "attribute" It is not possible to specify self::attribute::* because what follows the self:: axis name must be a test -- not another axis. The same problem exists for trying to determine if a node is a namespace node. Here is one solution to the attribute/namespace node-type identification problem: We can use a set equasion to determine whether or not the current node is a member of the set of all attributes of its parent. The set of all attributes of the parent of a node nd is: (1) ../@* The current node is: (2) . We can test if a node nd belongs to a node-set ns like this: (3) count(nd | ns) = count(ns) Substituting (1) and (2) in (3) we obtain: count(. | ../@*) = count(../@*) In the same way to test for a namespace we can use the following expression: count(. | ../namespace::*) = count(../namespace::*) I'm going to show how to use these two tests in my next snippet.

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<< XQuery.NET and XML >>



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