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By	Mark Wilson I am the creator of TopXML. I am available for international and local (Australia) contracts. I am a Solution Architect/Business Analyst. I have worked in IT in several countries (NZ, Australia, South Africa, UK) building and training teams for government and very large non-governmental organizations. I am ex-Microsoft Consulting Services. I wrote the first book on Microsoft XML published in 2000 called XML Programming with VB and ASP. Most recently I have been building tools for the SEO industry. Ask me for a 37 point SEO health-checkup for your website.
First Posted	12/03/2007
Times viewed	8959

Displaying every odd row a different color

This post contains attachments
v20010125232950.zip

Summary To display the background color of every odd row in a table in a different color you need to use the XPath position() function. This achieved using the mod operator.

To our <td> element we are going to add the bgcolor element to be silver if the mod operator returns false (0), which is achieved in the following code:
<td>
<xsl:if test=position() mod 2>
<xsl:attribute name=bgcolor>silver</xsl:attribute>
</xsl:if>

The HTML output for this transformation looks as follows:

Today's Headlines

Rescued penguins swim home

Bug mops up sewage

In the land of the colour-blind

Additional information
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> <xsl:template match="/headlines"> <html> <basefont face="Verdana" size="2" /> <body> <h2>Today's Headlines</h2> <table border="1"> <xsl:for-each select="article"> <tr> <td> <xsl:if test="position() mod 2"> <xsl:attribute name="bgcolor">silver</xsl:attribute> </xsl:if> <font color="blue"> <xsl:value-of select="text()" /> </font> </td> </tr> </xsl:for-each> </table> </body> </html> </xsl:template> </xsl:stylesheet>

Further additional information
<layout> <field name="card_id" caption="Card" info="Card number" format="link" /> </layout>

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