TopXML XSLT library : XSLT Sort - output entire xml file with new sort order

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<< XQuery .NET and XML >>

By	John Workman
First Posted	06/01/2003
Times viewed	959

XSLT Sort - output entire xml file with new sort order

Summary This transform will output the same xml document sorted according to the xpath variable.

The transform below will output the same xml document sorted according to the xpath variable. This seems like a simple thing to do, but I struggle with this one for a while, so I figured others probably have too. **NEW** The original transform was sorting based on an attribute. It was requested that there was a sort based on elements. So here goes, I hope this helps.

Additional information
<?xml version="1.0"?> <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> <xsl:output omit-xml-declaration = 'yes'/>  <xsl:template match='/'> <xsl:for-each select="node()"> <xsl:call-template name='processNode'/> </xsl:for-each> </xsl:template> <xsl:template name='processNode' match='node()'> <xsl:copy> <xsl:copy-of select="@*" /> <xsl:if test='*/* = ""'> <xsl:for-each select="node()"> <xsl:call-template name='processNode'/> </xsl:for-each> </xsl:if> <xsl:if test='not(*/* = "")'> <xsl:copy-of select="@*" /> <xsl:for-each select="node()"> <xsl:sort select='@LastName'/> <xsl:copy> <xsl:copy-of select="@*" /> </xsl:copy> </xsl:for-each> </xsl:if> </xsl:copy> </xsl:template> </xsl:stylesheet> SAMPLE <doc> <payroll> <record LastName="Workman" payrollID="123456" hours="40" rate="12.00" /> <record LastName="Miller" payrollID="223456" hours="40" rate="12.00" /> <record LastName="Adams" payrollID="323456" hours="40" rate="12.00" /> </payroll> </doc>

Further additional information
<?xml version="1.0"?> <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> <xsl:output omit-xml-declaration = 'yes'/>  <xsl:template match="EmployeeList"> <xsl:copy> <xsl:apply-templates> <xsl:sort select="LastName"/> <xsl:sort select="FirstName"/> </xsl:apply-templates> </xsl:copy> </xsl:template> <xsl:template match="*"> <xsl:copy> <xsl:apply-templates/> </xsl:copy> </xsl:template> </xsl:stylesheet> SAMPLE: <Doc> <EmployeeList> <Employee> <FirstName>Dean</FirstName> <LastName>Workman</LastName> <Street>123 a</Street> <City>New York</City> <State>NY</State> </Employee> <Employee> <FirstName>William</FirstName> <LastName>Andrews</LastName> <Street>123 W</Street> <City>Chicago</City> <State>IL</State> </Employee> <Employee> <FirstName>John</FirstName> <LastName>Workman</LastName> <Street>123 M</Street> <City>Atlanta</City> <State>GA</State> </Employee> </EmployeeList> </Doc>

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