System.XML

System.XML Contents

System.Xml.XmlEntityReference Class

System.Xml.XMLEntity Class

System.Xml.XmlElement Class

System.Xml.XmlDocumentType Class

System.Xml.XmlDocumentFragment Class

System.Xml.XmlDocument Class

System.Xml.XmlDeclaration Class

System.Xml.XmlDataDocument Class

System.Xml.XmlConvert Class

System.Xml.XmlComment Class

System.Xml.XmlCharacterData Class

System.Xml.XmlCDataSection Class

System.Xml.XmlAttributeCollection Class

System.Xml.XmlAttribute Class

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First posted :	03/24/2008
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The System.Xml.XmlImplementation Class

Supported Versions

.NET Framework 1.0, 1.1, 1.2

Public Members

Bold members are covered in the sample code.

Public Properties	Public Methods
	CreateDocument
	Equals
	GetHashCode
	GetType
	HasFeature
	ToString
	CreateDocument

Overview

In order for XmlDocument objects to share a NameTable, they must be created within the same implementation context. The XmlImplementation class can be used to establish this context.

Example (VB.NET): How to compare two XmlElement nodes from different XmlDocument objects that share the same NameTable.

In this example, we create two instances of the XmlDocument class using the XmlImplementation.CreateDocument method. We then create an XmlElement node for each document, assign it an InnerText value, and then compare these values.

Dim objXmlImplementation As New System.Xml.XmlImplementation

Dim objDocument1 As System.Xml.XmlDocument

Dim objDocument2 As System.Xml.XmlDocument

Dim objXmlElement1 As System.Xml.XmlElement

Dim objXmlElement2 As System.Xml.XmlElement

objDocument1 = objXmlImplementation.CreateDocument()

objDocument2 = objXmlImplementation.CreateDocument()

objXmlElement1 = objDocument1.CreateElement("node1")

objXmlElement1.InnerText = "Testing"

objXmlElement2 = objDocument2.CreateElement("node2")

objXmlElement2.InnerText = "Testing"

If (objXmlElement1.InnerText = objXmlElement2.InnerText) Then